[tex]3x^{6}-4x^{5}+2x^{4} - 8x^{3} +2x^{2}-4x+3=0[/tex] . разложить на множители. Created by vasiq141. algebra-ru

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May 2022 1 4 Report

[tex]3x^{6}-4x^{5}+2x^{4} - 8x^{3} +2x^{2}-4x+3=0[/tex] . разложить на множители

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$3x^{6}-4x^{5}+2x^{4} - 8x^{3} +2x^{2}-4x+3=3x^{4}(x^2+1)-4x^3(x^2+1)-x^2(x^2+\\+1)-4x(x^2+1)+3(x^2+1)=(x^2+1)(3x^4-4x^3-x^2-4x+3)=(x^2+\\+1)(3x^2(x^2+x+1)-7x(x^2+x+1)+3(x^2+x+1))=(x^2+1)(x^2+x+\\+1)(3x^2-7x+3)$

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