Найти условный экстремум ф-и [tex]z = xy^2[/tex] при [tex]x+2y=1[/tex]
Решение:
x = 1 - 2y
z = xy^2 = y^2 (1-2y) = y^2-2y^3
z' = 2y - 6y^2
Что делать дальше?
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