[tex]cos(6+3x)=- \frac{\sqrt{2} }{2} [/tex] решить уравнение. Created by KawaiiNeko. matematika-ru

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[tex]cos(6+3x)=- \frac{\sqrt{2} }{2} [/tex] решить уравнение

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JANEE $6+3x=arccos(- \frac{ \sqrt{2}}{2} )$
$6+3x=+-\frac{ 3*\ pi }{4} +2 \pi n$
$3x=+- \frac{3* \ pi }{4}-6+2 \pi n$
$x=+- \frac{\ pi }{4} -2+(2 \pi n)/3$ , где n принадлежит Z

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