tex]. Тогда сумма первых десяти членов равна...

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В арифметической прогрессии [tex] a_{3}+a_{7}=5, a_{4}=1 [/tex]. Тогда сумма первых десяти членов равна

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$a_{3}+a_{7}=5\\ 
a_{4}=1\\\\
2a_{1}+8d=5\\
a_{1}+4d=2.5\\
a_{5}=2.5\\\\
d=2.5-1=1.5\\ 
a_{1}=2.5-4*1.5=-3.5\\\\
 S_{10}=(2*-3.5+9*1.5)5=(-7+13.5)*5=32.5$

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tex]...

chetyre shkolnika sdelali v magazine pokupki pervyj kupil penal i lastik zaplatba629fcc5f0fb50a44b26d07e5a7733e 45213

sostavit programmu kotoraya zamenyaet v stroke s strochnye bukvy orus na p

s pomoshyu rasseivayushej linzy poluchili izobrazhenie predmeta vysotoj h6 sm opred

kazhdyj element kvadratnoj matricy razmerom nxn raven nulyu libo edinice najdite

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