tex]...

openkova413 @openkova413

July 2022 1 5 Report

дана арифметическая прогрессия где
[tex]a1 = \frac{5}{6} \: d = - \frac{1}{6} [/tex]
найдите
[tex]a37[/tex]

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sergeevaolga5

Ответ:

$a_{37}=-5\frac{1}{6}$

Объяснение:

$(a_n)\;a_1=\frac{5}{6},\;d=-\frac{1}{6},\;a_{37}=?\\\\a_n=a_1+d(n-1)\\a_{37}=a_1+36d\\a_{37}=\frac{5}{6}+36*(-\frac{1}{6})=\frac{5}{6}-6= -5\frac{1}{6}$

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