Помогите решить уравнение.
[tex] \sqrt{7+ \sqrt{x} } = \sqrt{11- \sqrt{x} } [/tex]
[tex] \sqrt{7+ \sqrt{x} } = \sqrt{11- \sqrt{x} } [/tex]
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√(7+√х)=√(11-√х) х≥07+√х=11-√х
2√х=4
√х=2
х=4