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[tex] \frac{27}{64} {m}^{3} - 0.008 {n}^{12} [/tex]
[tex] \frac{27}{64} {m}^{3} - 0.008 {n}^{12} [/tex]
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Ответ:
Объяснение:
27/64 m³ – 0,008n^12=(3/4m)³ –(0,2n^4)³= = (3/4 m -0,2n^4)(9/16 m²+0,15mn^4+0,04n^8)