Пожалуйста помогите) Решение логарифмических неравенств:
1) [tex] log_{ \frac{1}{3} } ( x+4)\ \textgreater \ log_{ \frac{1}{3} } ( x^{2}+ 2x-2) [/tex]
2) [tex]lg( 2x-3) \ \textgreater \ lg( x+1) [/tex]
3) [tex] \left \{ {{x-18 \ \textless \ 0} \atop { log_{5}x\ \textgreater \ 1 }} \right. [/tex]
4) [tex] \left \{ {{ log_{ \frac{1}{3} }x\ \textless \ -2 } \atop {x+1\ \textgreater \ 3}} \right. [/tex]
5) [tex] \left \{ {{ln x \geq 0} \atop {5-x \ \textless \ 0 }} \right. [/tex]
6) [tex] \left \{ {{ln x \leq 1} \atop {x+7\ \textgreater \ 0}} \right. [/tex]
1) [tex] log_{ \frac{1}{3} } ( x+4)\ \textgreater \ log_{ \frac{1}{3} } ( x^{2}+ 2x-2) [/tex]
2) [tex]lg( 2x-3) \ \textgreater \ lg( x+1) [/tex]
3) [tex] \left \{ {{x-18 \ \textless \ 0} \atop { log_{5}x\ \textgreater \ 1 }} \right. [/tex]
4) [tex] \left \{ {{ log_{ \frac{1}{3} }x\ \textless \ -2 } \atop {x+1\ \textgreater \ 3}} \right. [/tex]
5) [tex] \left \{ {{ln x \geq 0} \atop {5-x \ \textless \ 0 }} \right. [/tex]
6) [tex] \left \{ {{ln x \leq 1} \atop {x+7\ \textgreater \ 0}} \right. [/tex]
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Ответ:
Т.к. другие значения противоречат определению логарифма