Home
О нас
Products
Services
Регистрация
Войти
Поиск
Олеся18022000
@Олеся18022000
July 2022
1
4
Report
ЛЕГКИЙ ПРИМЕР
[tex]( \frac{1}{a^2-b^2} + \frac{b}{a^3+b^3} ): \frac{a^2}{a^6-b^6} =[/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
1)1/[(a-b)(a+b)+1/[(a+b)(a²-ab+b²)]=(a²-ab+b²+ab-b²)/[(a-b)(a³=b³)]=
=a²/[(a-b)(a³+b³)]
2)a²/[(a-b)(a³+b³)]*(a-b)(a²+ab+b²)(a³+b³)/a²=a²+ab+b²
1 votes
Thanks 0
Олеся18022000
Спасибо, всё верно!!!
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tex]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1)1/[(a-b)(a+b)+1/[(a+b)(a²-ab+b²)]=(a²-ab+b²+ab-b²)/[(a-b)(a³=b³)]==a²/[(a-b)(a³+b³)]
2)a²/[(a-b)(a³+b³)]*(a-b)(a²+ab+b²)(a³+b³)/a²=a²+ab+b²