решите неравенство
[tex] \frac{4x}{16 x^{2} -25} [/tex]≥[tex] \frac{5}{16 x^{2} -25} [/tex]
[tex] \frac{4x}{16 x^{2} -25} [/tex]≥[tex] \frac{5}{16 x^{2} -25} [/tex]
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Получится вот так :)