1)Якщо [tex]sin^{2}a=\frac{1}{4}...To.. cos^{2}a=[/tex] 2)Якщо [tex]cos^{2}a=\frac{1}{9}...To.. tg^{2}a[/tex]. Created by dimaonopko2020. algebra-ru

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1)Якщо [tex]sin^{2}a=\frac{1}{4}...To.. cos^{2}a=[/tex] 2)Якщо [tex]cos^{2}a=\frac{1}{9}...To.. tg^{2}a[/tex]

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MatrixOfsciences

Ответ:

1) cos²a = 3/4 = 0,75

2) tg²a = 8

Объяснение:

$1) \: \: {cos}^{2} a = 1 - {sin}^{2} a \\ {cos}^{2} a = 1 - \frac{1}{4} \\ {cos}^{2} a = \frac{3}{4} = 0.75$

$2) \: \: {sin}^{2}a + {cos}^{2} a = 1 | \div {cos}^{2} a\\ {tg}^{2} a + 1= \frac{1}{ {cos}^{2}a } \\ {tg}^{2} a = \frac{1}{ {cos}^{2}a } - 1 \\ {tg}^{2} a = \frac{1}{ \frac{1}{9} } - 1 = 9 - 1 = 8$

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