Найти производную: [tex]y= x^{8} - \sqrt{x} + \frac{3}{ \sqrt[3]{ x^{5} } } - \frac{1}{ x^{3} } [/tex] [tex]y= \sqrt[3]{3+ x^{5} } [/tex]. Created by 123dima456. matematika-ru

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July 2022 1 11 Report

Найти производную:
[tex]y= x^{8} - \sqrt{x} + \frac{3}{ \sqrt[3]{ x^{5} } } - \frac{1}{ x^{3} } [/tex]
[tex]y= \sqrt[3]{3+ x^{5} } [/tex]

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kmike21

Verified answer

$y'=(x^8-x^{1/2}+3x^{-5/3}-x^{-3})'=8x^7- \frac{1}{2}x^{-1/2}-5x^{-8/3}+3x^{-4}=$
$=8x^7- \frac{1}{2 \sqrt{x} }-\frac{5}{ \sqrt[3]{x^8} }}+\frac{3}{x^4}$

$y'=((3+x^5)^{1/3})'= \frac{1}{3} (3+x^5)^{-2/3}*5x^4=\frac{5x^4}{ \sqrt[3]{(3+x^5)^{2}} }$

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Answers & Comments

Verified answer

skolko sm u buratino

kakie vidy korrozii v zavisimosti ot mehanizma processa i formy korrozionnyh r4382914bb34bdb3958c633af50308556 64537

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po izvestnoj otnositelnoj pogreshnosti priblizhennogo chisla najti ego absolyutnuyu

nuzhno issledovanie funkcii zhelatelno podrobno yx36x29x4

pomogite s testom 1 2 1 a 3 b 4 v 1 2 23 a 5 b 4 v 6

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