Нужно найти производную y=[tex] \frac{ x^{2} -3x+1}{ x^{2} +x+1} [/tex]. Created by 123dima456. matematika-ru

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Нужно найти производную
y=[tex] \frac{ x^{2} -3x+1}{ x^{2} +x+1} [/tex]

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Giorgio

Verified answer

$y'= \frac{(2x-3)(x^2+x+1)-(x^2-3x+1)(2x+1)}{(x^2+x+1)^2} = \\ = \frac{2x^3+2x^2+2x-3x^2-3x-3-2x^3+6x^2-2x-x^2+3x-1}{(x^2+x+1)^2} = \frac{4x^2-4}{(x^2+x+1)^2} \\~~~~~$ Надеюсь, не запутаетесь))

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Giorgio Бывает...

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Answers & Comments

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skolko sm u buratino

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