Решите систему уравнений.
[tex] \left \{ {(3x+7y)^2=10y,} \atop {(3x+7y)^2=10x.}} \right. [/tex]
[tex] \left \{ {(3x+7y)^2=10y,} \atop {(3x+7y)^2=10x.}} \right. [/tex]
More Questions From This User See All
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(3x + 7y)^2 = 10y ==> (10y)^2 - 10y = 0 ==> 10y(10y-1) = 0 => y=0 , y=0,1
решением будут являться точки (0;0) и (0,1;0,1)