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√7(√7-√28)
(√18+√72)·√2
(3√5-4√3)·√5
2√2(3√18-[tex] \frac{1}{4} [/tex]√2+√32)
√7(√7-√28)
(√18+√72)·√2
(3√5-4√3)·√5
2√2(3√18-[tex] \frac{1}{4} [/tex]√2+√32)
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Verified answer
1) ... = 7-√(7*7*4)=7-14=-72) ... = √36+√144=6+12=18
3) ... = 3*5-4√15 = 15-4√15
4) ... = 6√36-1/2√2+2√(16*2) = 6*6-1/2√2+8√2 = 36+7,5√2