помогите!![tex]3a + \frac{1}{2a} = 4[/tex]если так, то [tex]9a {}^{2} + \frac{1}{4a {}^{2} } = [/tex]???. Created by milanayoungkyg. algebra-ru

tex]???...

milanayoungkyg @milanayoungkyg

August 2022 1 5 Report

помогите!!
[tex]3a + \frac{1}{2a} = 4[/tex]
если так, то
[tex]9a {}^{2} + \frac{1}{4a {}^{2} } = [/tex]
???

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Universalka

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$3a+\frac{1}{2a}=4\\\\(3a +\frac{1}{2a})^{2} =4^{2}\\\\9a^{2}+2*3a*\frac{1}{2a}+\frac{1}{4a^{2}}=16\\\\9a^{2}+3+\frac{1}{4a^{2}}=16\\\\9a^{2}+\frac{1}{4a^{2}}=16-3\\\\\boxed{9a^{2}+\frac{1}{4a^{2}}=13}$

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milanayoungkyg аа понятно спасибо))

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