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shadow0191
@shadow0191
July 2022
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2 производные пожалуйста[tex]y= \frac{9}{ \sqrt[5]{x^2+4x-5} }
y=In(tg2x)^3[/tex]
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sharadi
Verified answer
1) у= 9*(х² + 4х -5)^-1/5
y' = -9/5 * (х² + 4х -5)^4/5 * (2х + 4) = -9(2х +4)*⁵√(х² + 4х -5)
2) у = 3ln(tg2x)
y' = 3/tg2x * 1/Cos²2x * 2= 6/(tg2x * Cos²2x) = 6/(Sin2x*Cos2x)=12/Sin4x
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Answers & Comments
Verified answer
1) у= 9*(х² + 4х -5)^-1/5y' = -9/5 * (х² + 4х -5)^4/5 * (2х + 4) = -9(2х +4)*⁵√(х² + 4х -5)
2) у = 3ln(tg2x)
y' = 3/tg2x * 1/Cos²2x * 2= 6/(tg2x * Cos²2x) = 6/(Sin2x*Cos2x)=12/Sin4x