Решите, пожалуйста, уравнение:
[tex](144^{sinx})^{cosx} = \frac{1}{12}^{ \sqrt{3}sinx} [/tex]
[tex](144^{sinx})^{cosx} = \frac{1}{12}^{ \sqrt{3}sinx} [/tex]
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Answers & Comments
2sinxcosx=-√3sinx
sinx=0, x=πk
2cosx=-√3
cosx=-√3/2
x=+-(плюс минус) 5π/6+πк