Решить:[tex] \sqrt{3 ^{6} \times {2}^{4} \times {7}^{2} } [/tex][tex] \frac{0.7}{ \frac{5}{8} - \frac{3}{16} } [/tex]. Created by 0809010s. algebra-ru

tex]...

$1)\sqrt{3^{6}*2^{4} *7^{2}} =\sqrt{(3^{3})^{2}*(2^{2})^{2}*7^{2}}=3^{3}*2^{2}*7=27*4*7=756\\\\2)\frac{0,7}{\frac{5}{8}-\frac{3}{16}}=\frac{0,7}{\frac{10}{16}-\frac{3}{16}}=\frac{7}{10}:\frac{7}{16}=\frac{7}{10}*\frac{16}{7}=\frac{16}{10}=1,6$

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