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Ваня2142
@Ваня2142
July 2022
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Решите пожалуйста, срочно надо![tex] \lim_{x \to \ 1} \frac{ x^{2} +2x-3}{x-1} [/tex]
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Lesben
X²+2x-3=(x+3)(x-1)
(x+3)(x-1)/(x-1)=x+3
lim (x²+2x-3)/(x-1)= lim (x+3) = 1+3 =4
x→1 x→1
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Answers & Comments
(x+3)(x-1)/(x-1)=x+3
lim (x²+2x-3)/(x-1)= lim (x+3) = 1+3 =4
x→1 x→1