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sin[tex]\frac{sin^{3}\alpha-cos^{3}\alpha}{1+sin\alpha cos\alpha}+cos\alpha-sin\alpha[/tex]
Упростить выражение
sin[tex]\frac{sin^{3}\alpha-cos^{3}\alpha}{1+sin\alpha cos\alpha}+cos\alpha-sin\alpha[/tex]
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Answers & Comments
(sin^3 x - cos^3 x) / (1+sinx*cosx) + cosx - sinx = (sinx - cosx)(sin^2 x + sinx*cosx + cos^2 x) / (1+sinx*cosx) + cosx - sinx = sinx - cosx + cosx - sinx = 0