помогите решить систему. очень надо
[tex] \left \{ {{log _{9}(x-y)= \frac{1}{2} } \atop {log_{64}x-log_{64}y= \frac{1}{3} }} \right. [/tex]
[tex] \left \{ {{log _{9}(x-y)= \frac{1}{2} } \atop {log_{64}x-log_{64}y= \frac{1}{3} }} \right. [/tex]
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Verified answer
Log9 (x-y) =1/2log64 x -log64 y = 1/3
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x-y=√9
log64 x/y=1/3
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x-y=3
∛64=x/y
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x-y=3
x/y=4
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x-y=3, x=y+3
x=4y
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y+3=4y, 3y=3, y=1
x=4.1=4
/x,y/=/4,1/