Даю 15 баллов.[tex] (4^{k+1} +6*4^{k}) ^{3} / ( 8^{k+1} +2*8^{k} )^{2} [/tex]. Created by montiriy12zokboss123. algebra-ru

tex]...

October 2021 1 8 Report

Даю 15 баллов.[tex] (4^{k+1} +6*4^{k}) ^{3} / ( 8^{k+1} +2*8^{k} )^{2} [/tex]

A1dar $\frac{(4^{k+1} +6*4^k)^3}{( 8^{k+1} +2*8^k)^2}=\frac{(4^k(4+6))^3}{(8^k(8+2))^2}=\frac{4^{3k}*10^3}{8^{2k}*10^2}=\frac{2^{6k}*10}{2^{6k}}=10$

2 votes Thanks 1