Помогите решить
[tex]$$ \frac{x-3}{6} $$+ x = $$ \frac{2x-1}{3} $$ - $$ \frac{4-x}{2} $$[/tex]
[tex]$$ \frac{x-3}{6} $$+ x = $$ \frac{2x-1}{3} $$ - $$ \frac{4-x}{2} $$[/tex]
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Answers & Comments
х-3+6х=2(2х-1)-3(4-х)
х-3+6х=4х-2-12+3х
х+6х-4х-3х=-2-12+3
0х=-11
корней нет