Помогите решить
[tex]\frac{x-3}{6} $$+ x = $$ \frac{2x-1}{3} $$ - $$ \frac{4-x}{2} $$
[/tex]
[tex]\frac{x-3}{6} $$+ x = $$ \frac{2x-1}{3} $$ - $$ \frac{4-x}{2} $$
[/tex]
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