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July 2022 1 2 Report

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[tex] \sqrt[3]{0,3}* \sqrt[3]{-0,09} [/tex]
[tex] \sqrt[3]{ 27^{2} } *(4 \frac{17}{27} )*36 ^{ -\frac{1}{2} } [/tex]
[tex] \frac{ 27^{-3}* 256^{4} * 88^{2} }{ 16^{7} * 9^{9} * 45^{-1} } [/tex]
[tex] \sqrt[4]{54*25} [/tex]
[tex] \sqrt[3]{-20*25*128} [/tex]

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NNNLLL54

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$\sqrt[3]{0,3}*\sqrt[3]{-0,09}=-\sqrt[3]{0,3^3}=-0,3 \\\\\sqrt[3]{27}*(4\frac{17}{27})*36^{-\frac{1}{2}}=\sqrt[3]{3^3}\cdot \frac{125}{27}\cdot \frac{1}{\sqrt{36}}=\frac{3\cdot 125}{27\cdot 6}=\frac{125}{54}\\\\\frac{27^{-3}\cdot 256^4\cdot 88^2}{16^7\cdot 9^9\cdot 45^{-1}}=\frac{3^{-3}\cdot 2^{32}\cdot 11^2\cdot 2^6}{2^{28}\cdot 3^{18}\cdot 5^{-1}\cdot 3^{-2}}=\frac{2^{10}\cdot 11^2\cdot 5}{3^{19}}\\\\\sqrt[4]{54\cdot 25}=\sqrt[4]{2\cdot 3^3\cdot 5^2}\\\\\sqrt[3]{-20\cdot 25\cdot 128}=$

$=-\sqrt[3]{2^2\cdot 5^3\cdot 2^7}=-\sqrt[3]{2^9\cdot 5^3}=-2^3\cdot 5=-40$

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