Найдите сумму бесконечной геометрической прогресии: -6; 1; -[tex] \frac{1}{6} [/tex];...
а). -7[tex] \frac{1}{5} [/tex]
б). 5[tex] \frac{1}{7} [/tex]
в). 7[tex] \frac{1}{5} [/tex]
г). -5[tex] \frac{1}{7} [/tex]
а). -7[tex] \frac{1}{5} [/tex]
б). 5[tex] \frac{1}{7} [/tex]
в). 7[tex] \frac{1}{5} [/tex]
г). -5[tex] \frac{1}{7} [/tex]
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Verified answer
B1=-6 b2=1q=b2/b1=-1/6
S=b1/(1-q)=-6:(1+1/6)=-6:7/6=-6*6/7=-36/7