Решить неравенства С ОБЪЯСНЕНИЕМ:
[tex]1) \sqrt{ 3^{x} }\ \textless \ 16[/tex]
[tex]2) ( 3-\sqrt{3} )^x\ \textgreater \ 6[/tex]
[tex]1) \sqrt{ 3^{x} }\ \textless \ 16[/tex]
[tex]2) ( 3-\sqrt{3} )^x\ \textgreater \ 6[/tex]
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1(√(3^x)²<16²
3^x<256
x<log(3)256
x∈(-∞;log(3)256)
2
x>log(3-√3)6
x∈(log(3-√3)6;∞)