[tex]sin^{6}+cos^{6}=sin^{2} cos^{2}[/tex]. Created by Ituha. algebra-ru

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July 2022 1 9 Report

[tex]sin^{6}+cos^{6}=sin^{2} cos^{2}[/tex]

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krolikzajcev

$(\sin^2 x +\cos^2 x)(\sin^4 x-\sin^2 x\cos^2 x+\cos^4 x)=\sin^2 x\cos^2 x\\sin^4 x-2\sin^2 x\cos^2 x+\cos^4 x=0\\(\cos^2 x-\sin^2 x)^2=0\\\cos 2x=0\\2x=\pi /2 +\pi k\\x=\pi /4+\pi k/2$

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Answers & Comments

1 v urne 3 belyh i 7 krasnyh sharov naugad vynimayut odin iz sharov a potom 2

tekst na anglijskom prostymi predlozheniyami kak ya zabochus o zdorove

v shkatulke lezhat 3 serebryanye i 3 zolotye monety naugad berut 2 monety najdi7b5bb3a34e4f8ef126033da176b12177 14959

v shkatulke lezhat 3 serebryanye i 3 zolotye monety naugad berut 2 monety najdi

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dva odinakovyh metallicheskih sharika zaryazheny raznoimyonno tak chto velichina zaryad

reshite uravnenieb61bfe61043ae440c443f21b80208f1a 8495

uprostite sinarccosx arcsiny6d931c6f6fb3bdaa8a0b20ca92442a20 14477

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