[tex]1+sin2x=(cos3x+sin3x)^{2}[/tex]. Created by Ituha. algebra-ru

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Ituha @Ituha

July 2022 1 7 Report

[tex]1+sin2x=(cos3x+sin3x)^{2}[/tex]

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Verified answer

1 + Sin2x = (Cos3x + Sin3x)²

1 + Sin2x = Cos²3x + 2Sin3xCos3x + Sin²3x

1 + Sin2x = 1 + Sin6x

Sin6x - Sin2x = 0

$2Sin\frac{6x-2x}{2} Cos\frac{6x+2x}{2}=0\\\\Sin2xCos4x=0\\\\1)Sin2x=0\\\\2x=\pi n,nez\\\\x=\frac{\pi n }{2},nez\\\\2)Cos4x=0\\\\4x=\frac{\pi }{2}+\pi n,nez\\\\x=\frac{\pi }{8}+\frac{\pi n }{4},nez$

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Answers & Comments

Verified answer

1 v urne 3 belyh i 7 krasnyh sharov naugad vynimayut odin iz sharov a potom 2

tekst na anglijskom prostymi predlozheniyami kak ya zabochus o zdorove

v shkatulke lezhat 3 serebryanye i 3 zolotye monety naugad berut 2 monety najdi7b5bb3a34e4f8ef126033da176b12177 14959

v shkatulke lezhat 3 serebryanye i 3 zolotye monety naugad berut 2 monety najdi

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dva odinakovyh metallicheskih sharika zaryazheny raznoimyonno tak chto velichina zaryad

reshite uravnenieb61bfe61043ae440c443f21b80208f1a 8495

uprostite sinarccosx arcsiny6d931c6f6fb3bdaa8a0b20ca92442a20 14477

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