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ForeverRotterhead
@ForeverRotterhead
July 2022
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√5-√3 / √45-√27 =
[tex] \frac{61}{ 16 +4∛ 3 + ∛9 } + ∛3[/tex] =
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Бахтияр2004
(√5-√3)÷(3√5-3√3)=(√5-√3)÷(√5-√3)3=1/3
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Answers & Comments
(√5-√3)÷(3√5-3√3)=(√5-√3)÷(√5-√3)3=1/3