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Lantica
@Lantica
August 2022
2
10
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Какие в этом выражении корни?
[tex]\sqrt{5} x^{2} -10x+5=0[/tex]
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Answers & Comments
boss9800
D=b^2-4ac
b=-10
a=√5
c=5
D=100-4*√5*5=100-20√5
x1=(10+√(100-20√5))/2√5
x2=(10-√(100-20√5))/2√5
1 votes
Thanks 1
Dимасuk
дроби сократите
sedinalana
D=b²-4ac
D=100-20√5
3 votes
Thanks 1
Lantica
А как вы сократили (10-2√(25-5√5))/2√5 до √5-√(5-√5)
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Answers & Comments
b=-10
a=√5
c=5
D=100-4*√5*5=100-20√5
x1=(10+√(100-20√5))/2√5
x2=(10-√(100-20√5))/2√5
D=100-20√5