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MaTEMATuK3000
@MaTEMATuK3000
August 2021
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[tex]( x+ \frac{3- x^{2} }{x-1} ) : \frac{x-3}{1- x^{2} } [/tex]
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sedinalana
Verified answer
1)x+(3-x²)/(x-1)=(x²-x+3-x²)/(x-1)=(3-x)/(x-1)
2)(3-x)/(x-1):(x-3)/(1-x²)=(x-3)/(1-x)*(1-x)(1+x)/(x-3)=1+x
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1)x+(3-x²)/(x-1)=(x²-x+3-x²)/(x-1)=(3-x)/(x-1)2)(3-x)/(x-1):(x-3)/(1-x²)=(x-3)/(1-x)*(1-x)(1+x)/(x-3)=1+x