ОЧЕНЬ СРОЧНО решите показательные неравенства
1) [tex]3\frac{x-5}{2} \geq 3\sqrt{5}[/tex]
2)[tex](\frac{2}{3})^{x^{2}+5x } \ \textgreater \ 1[/tex]
3)[tex](\frac{1}{3})^{\sqrt{x+2} } \ \textgreater \ (\frac{1}{3} )^{x}[/tex]
1) [tex]3\frac{x-5}{2} \geq 3\sqrt{5}[/tex]
2)[tex](\frac{2}{3})^{x^{2}+5x } \ \textgreater \ 1[/tex]
3)[tex](\frac{1}{3})^{\sqrt{x+2} } \ \textgreater \ (\frac{1}{3} )^{x}[/tex]
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Answers & Comments
1) 3*(x-5) / 2 ≥ 3√5
x-5/2 ≥ √5
x-5 ≥ 2√5
x ≥ 2√5 + 5.
2) (2/3)^x^2+5x > 1
(2/3)^x^2+5x > (2/3)^0
x^2 + 5x < 0
x*(x+5) < 0
Система неравенств:
x Є (-5;0)
3)
x Є (2; +бесконечность)
x>2.