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VSKHHolmes41928
@VSKHHolmes41928
August 2021
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Решите неравенство [tex] \frac{ x^{2} }{2} \ \textless \ \frac{2x+2}{3} [/tex]
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ShirokovP
Verified answer
Домножим на 6
3x^2 < 2(2x + 2)
3x^2 - 4x - 4 < 0
D= 16 + 4*4*3 = 64 = 8^2
x1 = ( 4 + 8)/6 = 2;
x2= ( 4 - 8)/6 = - 2/3;
x ∈ ( - 2/3; 2)
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Answers & Comments
Verified answer
Домножим на 63x^2 < 2(2x + 2)
3x^2 - 4x - 4 < 0
D= 16 + 4*4*3 = 64 = 8^2
x1 = ( 4 + 8)/6 = 2;
x2= ( 4 - 8)/6 = - 2/3;
x ∈ ( - 2/3; 2)