Решите пожалуйста: [tex] 3^{x+2}+ 3^{x-1} \leq 28 [/tex]. Created by Alexsandr7643. algebra-ru

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July 2022 2 15 Report

Решите пожалуйста:
[tex] 3^{x+2}+ 3^{x-1} \leq 28 [/tex]

Verified answer

$3^{x+2}+3^{x-1} \leq 28 \\ (3^3+1)*3^{x-1} \leq 28 \\ 28*3^{x-1} \leq 28 \\ 3^{x-1} \leq 1 \\ x-1 \leq 0 \\ x \leq 1$

Ответ: x≤1

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$3^{x+2}+3^{x-1} \leq 28\\\\3^x*3^2+3^x*3^{-1} \leq 28\\\\3^x*9+3^x* \frac{1}{3} \leq 28\\\\3^x(9+ \frac{1}{3}) \leq 28\\\\3^x* \frac{28}{3} \leq 28|: \frac{28}{3} \\\\3^x \leq 3^1\\\\x \leq 1 \\\\x\in(-\infty;1]$

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