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rom4ik36899
@rom4ik36899
August 2022
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Решите графически систему уравнений [tex] \left \{ {{x^{2}+ (y-3)^{2}=25 } \atop {{3x+2y=0} \atop {{{3x+4y-12=0}} \right. [/tex]
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karinabatueva
Из второго уравнения
2y = 3x - 30
y = 1,5x - 15
Подставляем в 1-е уравнение
x^2 - (1,5x - 15)^2 = 100
x^2 - 2,25x^2 + 45x - 225 - 100 = 0
1,25x^2 - 45x + 325 = 0
x^2 - 36x + 260 = 0
x1 = 26; у1 = 24
x2 = 10; у2 = 0
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Answers & Comments
2y = 3x - 30
y = 1,5x - 15
Подставляем в 1-е уравнение
x^2 - (1,5x - 15)^2 = 100
x^2 - 2,25x^2 + 45x - 225 - 100 = 0
1,25x^2 - 45x + 325 = 0
x^2 - 36x + 260 = 0
x1 = 26; у1 = 24
x2 = 10; у2 = 0