[tex]( \frac{1}{3} \sqrt{39} - \frac{1}{2} \sqrt{26}+ \frac{1}{6} \sqrt{65} ) [/tex] ÷ [tex] \frac{1}{6} \sqrt{13} + \sqrt{18} [/tex]
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(1/3*√3*√13-1/2*√2*√3+1/6*√5*√13)=√13*(√3/3-√2/2+√5/6):√13/6==√13*(√3/3-√2/2+√5/6)*6/√13=2√3-3√2+√5
2√3-3√2+√5+3√2=2√3+√5