даю 30 баллов! пожалуйста, помогите решить неравенство, с пояснением
[tex]\frac{x^{3}-x^{2} +x-1}{x+8}[/tex] [tex]\leq 0[/tex]
[tex]\frac{x^{3}-x^{2} +x-1}{x+8}[/tex] [tex]\leq 0[/tex]
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+ + + + + (-8) - - - - - [1] + + + + +
Ответ : x ∈ ( - 8 ; 1]