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@chikipiki
July 2022
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ПОМОГИТЕ!!!!!
Найдите
[tex]a {}^{2} + \frac{4}{a {}^{2} } [/tex]
Если известно ,что
[tex]a {}^{2} + 6a = 2[/tex]
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2407Alexa
А²+(4/а²)=?,
если а²+6а=2
а²+6а-2=0
D=(-6)²-4×1×(-2)=36+8=44
a1=(-6-√44)/2×1=(-6-6,63)/2=(-12,63)/2=-6,315
a2=(-6+√44)/2×1=(-6+6,63)/2=0,63/2=0,315
(a1)²+(4/(a1)²)=(-6,315)²+(4/(-6,315)²)=39,872+(4/39,872)=39,872+0,100=39,972.
(a2)²+(4/(a2)²)=0,315²+(4/(0,315)²)=0,099+(4/0,099)=0,099+40,312=40,411.
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Answers & Comments
если а²+6а=2
а²+6а-2=0
D=(-6)²-4×1×(-2)=36+8=44
a1=(-6-√44)/2×1=(-6-6,63)/2=(-12,63)/2=-6,315
a2=(-6+√44)/2×1=(-6+6,63)/2=0,63/2=0,315
(a1)²+(4/(a1)²)=(-6,315)²+(4/(-6,315)²)=39,872+(4/39,872)=39,872+0,100=39,972.
(a2)²+(4/(a2)²)=0,315²+(4/(0,315)²)=0,099+(4/0,099)=0,099+40,312=40,411.