Помогите пожалуйста. Решите уравнение:а)14(2х-3)-5(х+4)=2(3х+5)+5х
б)[tex] \frac{x-1}{3} +2= \frac{x-1}{6} [/tex]
в)[tex] \frac{x-2}{6} + \frac{x-1}{15} =3- \frac{3-x}{12} [/tex]
г)[tex] \frac{9x-6}{2} - \frac{8+3x}{3} =-1[/tex]
б)[tex] \frac{x-1}{3} +2= \frac{x-1}{6} [/tex]
в)[tex] \frac{x-2}{6} + \frac{x-1}{15} =3- \frac{3-x}{12} [/tex]
г)[tex] \frac{9x-6}{2} - \frac{8+3x}{3} =-1[/tex]
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А.14(2х-3)-5(х+4)=2(3х+5)+5х
28х-42-5х-20=6х+10+5х
28х-5х-6х-5х=10+42+20
12х=72
х=72:12
х=6
б.
(х-1)/3 +2=(х-1)/6
2(х-1)+12=х-1
2х-х=-1-12+2
х= - 11
в.
(х-2)/6+(х-1)/15=3- (3-х)/12
10(х-2)+4(х-1)=3*60-5(3-х)
10х-20+4х-4=180-15+5х
10х+4х-5х=180-15+20+4
9х=189
х=189:9
х=21
г.
(9х-6)/2 - (8+3х)/3= -1
3(9х-6)-2(8+3х)= -6
27х-18-16-6х=-6
27х-6х= -6+18+16
21х=28
х= 28/21=4/3=1 1/3