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MЭRI
@MЭRI
July 2022
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помогите пожалуйста,срочно! решить неравенство. [tex] x^{2} (3-x)(2x+4)\ \textless \ 0[/tex]
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Utem
X²(3-x)(2x+4)<0
x<0 x<0 x<0
3-x<0 -x<-3 x>3
2x+4<0 2x<-4 x<-2
x∈(-∞;-2)∪(3;∞)
1 votes
Thanks 1
MЭRI
спасибо,а можете еще одно посмотреть? http://znanija.com/task/19040721
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Answers & Comments
x<0 x<0 x<0
3-x<0 -x<-3 x>3
2x+4<0 2x<-4 x<-2
x∈(-∞;-2)∪(3;∞)