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mrchekov
@mrchekov
July 2022
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Найдите область определения функции:
f(x)= ㏑[tex] \frac{4x+8}{3x-9} [/tex]
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dasdasfa
F(x)=ln ((4x+8)/(3x-9))
4x+8) /(3x-9)>0
y=4*3(x+2)(x-3); x≠ 3
y=0; x=-2 + - +
-------------(-2) ------------------3------------------->x
//////////////////// /////////////////////////////////
D(f)=(-∞;-2) ∪(3;+∞)
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Answers & Comments
4x+8) /(3x-9)>0
y=4*3(x+2)(x-3); x≠ 3
y=0; x=-2 + - +
-------------(-2) ------------------3------------------->x
//////////////////// /////////////////////////////////
D(f)=(-∞;-2) ∪(3;+∞)