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Koari
@Koari
July 2022
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Преобразование выражения:
[tex]( \frac{ m^{2} +n^{2} }{m^{2}n^{2}} *( \frac{1}{m^{2}} - \frac{1}{n^{2} } )-( \frac{1}{p^{2} } - \frac{1}{n^{2} }) * \frac{p^{2}+n^{2}}{p^{2}n^{2}} ): \frac{p^{2} +m^{2}}{p^{2}m^{2}} [/tex]
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wejde
Verified answer
1) 1/m²-1/n²=n²-m²/n²m²
2) (m²+n²)*(n²-m²)/m⁴n⁴=n⁴-m⁴/m⁴n⁴
3) 1/p²-1/n²=n²-p²/p²n²
4) (n²-p²)*(p²+n²)/p⁴n⁴=n⁴-p⁴/p⁴n⁴
5) (p⁴n⁴-p⁴m⁴-m⁴n⁴+p⁴m⁴)/m⁴n⁴p⁴=p⁴n⁴-p⁴m⁴/m⁴n⁴p⁴=n⁴-m⁴/m⁴n⁴
6) (n⁴-m⁴)*(p²m²)/m⁴n⁴(p²+m²)=(p²n⁴-m⁴p²)/(p²m²+m²n⁴)
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Koari
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Answers & Comments
Verified answer
1) 1/m²-1/n²=n²-m²/n²m²2) (m²+n²)*(n²-m²)/m⁴n⁴=n⁴-m⁴/m⁴n⁴
3) 1/p²-1/n²=n²-p²/p²n²
4) (n²-p²)*(p²+n²)/p⁴n⁴=n⁴-p⁴/p⁴n⁴
5) (p⁴n⁴-p⁴m⁴-m⁴n⁴+p⁴m⁴)/m⁴n⁴p⁴=p⁴n⁴-p⁴m⁴/m⁴n⁴p⁴=n⁴-m⁴/m⁴n⁴
6) (n⁴-m⁴)*(p²m²)/m⁴n⁴(p²+m²)=(p²n⁴-m⁴p²)/(p²m²+m²n⁴)