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Избавьтесь от иррациональности в знаменателе дроби:
[tex] \frac{5\sqrt{7}}{\sqrt{7}+\sqrt{2}} [/tex]

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NNNLLL54

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$\frac{5\sqrt7}{\sqrt7+\sqrt2} = \frac{5\sqrt7(\sqrt7-\sqrt2)}{(\sqrt7+\sqrt2)(\sqrt7-\sqrt2)} =\frac{5\sqrt7\cdot (\sqrt7-\sqrt{2})}{7-2}=\sqrt7(\sqrt7-\sqrt2)=7-\sqrt{14}$

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rrrrtttt01 August 2022 | 0 Ответы

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rrrrtttt01 August 2022 | 0 Ответы

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rrrrtttt01 August 2022 | 0 Ответы

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