[tex] \sqrt \frac{4x+32}{7}=6; \sqrt \frac{4}{3x-17}=1/2; \sqrt \frac{5}{8-3x}=1/13 [/tex]. Created by arina1404ap98. algebra-ru

1) Возводим в квадрат.Получается: 4х+32=36*74х=220х=55.2) 3x-17=163x=33x=113) 8-3x=845-3x=8373x=-837x=-279

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July 2022 1 31 Report

[tex] \sqrt \frac{4x+32}{7}=6; \sqrt \frac{4}{3x-17}=1/2; \sqrt \frac{5}{8-3x}=1/13 [/tex]

Answers & Comments

Bloodyasha 1) Возводим в квадрат.
Получается:
$\frac{4x+32}{7} = 36$
4х+32=36*7
4х=220
х=55.
2) $\frac{4}{3x-17} = \frac{1}{4}$
3x-17=16
3x=33
x=11
3) $\frac{5}{8-3x} = \frac{1}{169}$
8-3x=845
-3x=837
3x=-837
x=-279

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