Решите уравнения
а)[tex]x^2(x=1)=9(x+1)[/tex]
б)[tex]\frac{16}{x^2+x} - \frac{6}{x^2-x} =\frac{1}{x}[/tex]
в)[tex]\sqrt{\frac{3}{x-4}}=2[/tex]
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Решите уравнения
а)[tex]x^2(x=1)=9(x+1)[/tex]
б)[tex]\frac{16}{x^2+x} - \frac{6}{x^2-x} =\frac{1}{x}[/tex]
в)[tex]\sqrt{\frac{3}{x-4}}=2[/tex]
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