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Хамелеон0
@Хамелеон0
August 2022
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СРОЧНО! Алгебра! 10 класс!
1) sin²x + 2sinX · cosX - 3cos²X =0
2) cos5X= -[tex] \frac{1}{2} [/tex]
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Answers & Comments
kamron971
1)sin^2x+2sinx*cosx-3cos^2x=0 |÷cos^2x
tg^2x+2tgx-3=0
tgx=t
t^2+2t-3=0
x1=-3(не верно) ,x2=1
tgx=1
x=πn,n€Z
2)cos5x=-1/2
5x=+-2π/3+2πn. ,|÷5
x=+-2π/15+2πn/5, n€Z
1 votes
Thanks 1
Хамелеон0
а можете еще здесь решить - http://znanija.com/task/23029427
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Answers & Comments
tg^2x+2tgx-3=0
tgx=t
t^2+2t-3=0
x1=-3(не верно) ,x2=1
tgx=1
x=πn,n€Z
2)cos5x=-1/2
5x=+-2π/3+2πn. ,|÷5
x=+-2π/15+2πn/5, n€Z