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Asetaset9
@Asetaset9
August 2022
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Решите неравенства:
а) [tex]( \frac{1}{3} )^{x} \geq 27[/tex]
б) [tex]( \sqrt{6} ^{x} ) \leq \frac{1}{36} [/tex]
в) [tex]0.2 ^{x} \leq \frac{1}{25} [/tex]
г) [tex](1.5) ^{x} \ \textless \ 2.25[/tex]
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MegaMan2
А) (1/3)^x <= (1/3)^-3
x<= -3
б) 6^(x/2)<= 6^-2
x/2 <= -2
x<= -4
в) (1/5)^x >= (1/5)^2
x >= 2
г) (1,5)^x < (1,5)^2
x < 2
2 votes
Thanks 1
Asetaset9
А подробное решение? :С
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Answers & Comments
x<= -3
б) 6^(x/2)<= 6^-2
x/2 <= -2
x<= -4
в) (1/5)^x >= (1/5)^2
x >= 2
г) (1,5)^x < (1,5)^2
x < 2