Дано неравенство 0,82^3x2−12x<1. В каких пределах находится x?
[tex]0,82^{3x^{2}-12x } \ \textless \ 1[/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.